Computer Science, asked by jyotimdoddamani123, 10 months ago

plz tell the answer for this questions.​

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Answered by bktbunu
1

Explanation:

Dual of an expression requires interchanging

+ with .

. with +

0 with 1

1 with 0

41. A + A'B = (A+A')(A+B) = 1.(A+B) = A+B

dual of A+B = AB

complemlement of an expression E is E'. Before complementing simplify the expression.

42. A'(BC'+BC) = A'B(C'+C) = A'B as C'+C = 1

complemlement of the above expression= (A'B)' = (A')'+ B' = A+B'

43. complement of AB'+C'D' = (AB'+C'D')' = (AB')'(C'D')' = (A'+B)(C+D)

44. X'Y'+XY'Z = Y'(X'+XZ) = Y'(X'+X)(X'+Z) = Y'(X'+Z)

complement of the above expression= (Y'(X'+Z))' = (Y')'+(X'+Z)' = Y+((X')'Z') = Y+XZ'

45. XY+Y'Z+ZZ'=XY+Y'Z as ZZ'=0

complement of the above expression= (XY+Y'Z)' = (XY)' (Y'Z)' = (X'+Y')(Y+Z')

46. X+XY'+X'Z' = X(1+Y')+X'Z' = X+X'Z = (X+X')(X+Z) = 1(X+Z) = X+Z

complement if the above expression = (X+Z)' = X'Z'

Answered by shauryarastogi538888
0

Answer:

above answer is correct

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