Math, asked by davkanika0824, 5 months ago

Plz tell the answer of the above question it's very urgent !!!!!

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Answers

Answered by Anonymous

Answer:

$\implies - \dfrac{20}{27}$

Step-by-step explanation:

$\implies \sf \dfrac{x^2 - (x+2)(x+3)}{6x+1} = \dfrac{2}{3}$

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$\implies \sf \dfrac{x^2 - (x+2) \times (x+3)}{6x+1} = \dfrac{2}{3} , \: x \neq - \dfrac{1}{6}$

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$\implies \sf \dfrac{x^2 - (x^2 + 3x + 2x + 6)}{6x + 1} = \dfrac{2}{3}$

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$\implies \sf \dfrac{x^2 - (x^2 + 5x + 6)}{6x+1} = \dfrac{2}{3}$

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$\implies \sf \dfrac{x^2 - x^2 - 5x - 6}{6x+1} = \dfrac{2}{3}$

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$\implies \sf \dfrac{-5x-6}{6x+1} = \dfrac{2}{3}$

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$\implies \sf 3(-5x - 6) = 2(6x + 1)$

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$\implies \sf -15x - 18 = 2(6x + 1)$

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$\implies \sf -15x - 18 = 12x + 2$

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$\implies \sf 15x - 12x = 2 + 18$

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$\implies \sf 27x = 2 + 18$

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$\implies \sf -27x = 20$

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$\implies \sf x = - \dfrac{20}{27}, \: x \neq - \dfrac{1}{6}$

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$\qquad \large{\underline{\boxed{\bf x = - \dfrac{20}{27}}}}$

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