Question

plz tell the answer... plzz no faltu answers pplz thodi daya krdo plz​

Answer 1

Answer:

64

Step-by-step explanation:

angle ACD =58

Angle ACD=Angle CDA

therefore angle CDA =58

angle CAD = 180-(58+58)

= 180-116

= 64

Answer 2

Answer:

Angle ACD = 58 °

Now , since triangle ACD is isosceles , hence ,

Angle CAD = Angle CDA = X °

By angle sum property ,

X + X + 58 = 180

2X = 122 °

X = 61°.

Now , Angle CDA = 61°

By linear pair , Angle ADB = ( 180 - 61 ) = 119°

Since , triangle ADB is also isosceles , hence ,

Angle DAB = Angle DBA = Y

By angle sum property ,

Y + Y + 119 = 180

2Y = 61

Y = 61 / 2 °

Now , Angle CAB = Angle CAD + Angle DAB

Angle CAB = 61 + 61 / 2 °

Angle CAB = 91.5 ° or 183 / 2

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