Question

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Answer 1

Answer:

Let AB and CD be the equal chords.

Let O be the centre of circle.

Let E and F be the mid-points of the chords.

Therefore,

EB=AE

CF=DF

Equal chords are equidistant from the centre.

∴OE=OF

Now in △OAB and △OCD

OA=OD(Radius of circle)

AB=CD(Given)

OB=OC(Radius of circle)

By SAS congruency,

△OAB≅△OCD

Now by C.P.C.T.,

∠AOB=∠COD

Hence proved that the line joining the mid-point of two equal chords of a circle subtends equal angles with the chord.

Answer 2

Answer:

pata nhi

Step-by-step explanation:

likhe ka man nhi h