plz tell the answer with diagram
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Steps of construction:
1.Draw a line segment XY
2.Locate Q,R on XY such that QR=3cm
3.Construct a line segment SR, sufficiently large, such that ∠R=90 ^∘
4.With Q as centre and radius 4cm draw an arc, cutting RS at P; join PR.
Then, PQR is the required triangle
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I think this is helpful opp=3
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