Question

plz tell the answer with explanation
options are given
explanation is must.....​

Answer 1

Answer:

a2v1=a1v2. (C)

Area of cylinder=2πrh

Volume of cylinder=πr^2h

Let radius of 1st cylinder = r1

Let radius of 2nd cylinder=r2

v1 = π×(r1)^2×a2...... (i)

v2 = π×(r2)^2×a1......(ii)

Surface area of sheet=Length×Breadth

=a1×a2

Surface area of sheet=Area of 1st cylinder=Area of 2nd cylinder

For 1st cylinder, a1×a2=2π×r1×a2

r1=a1/2π

Similarly, r2=a2/2π

Put r1 in (i) and r2 in (ii)

v1=π×(a1)^2×a2/4π^2=(a1)^2×a2/4π

So 4π=(a1)^2×a2/v1....(iii)

Similarly, 4π=(a2)^2×a1/v2......(iv)

Equate(iii) and(iv)

a1v2=a2v1 (C)

Answer 2

Answer:

in case of first cylinder,

2πr1=a1

r1=ak1

height=a2

v1=π*r1^2*a2

=π*k^2*a1^2*a2

in case of second cylinder,

2πr2=a2

r2=ka2

height=a1

v2=π*r2^2**a1

v2=π*k^2*a2^2*a1

(v1/v2)=(a1^2*a2)/(a2^2*a1)

=(a1/a2)

v1/a1=v2/a2(Option 4)