plz tell the corect answer guys
Answers
Answer:
no.1
Step-by-step explanation:
Question 1st
1. 60°
2. 55°
3.
Question 2nd
1. 50°
2.
3. 45°
Answer:
Step-by-step explanation:
1. In Circle, Central Angle (at O) = Twice the Inscribed angle (at C)
x = 2 * 30°
x= 60°
2. Using Same Property (1)
Central Angle (at O) = Twice the Inscribed angle (at C)
110° = 2x
x = 55°
3. In Cirlce, Angles formed by the same arc(A,B) on the circumference of the circle is always equal.
so, ∠AOB = ∠ACB
80° = x
4 . AOB is a straight line.
∠AOC + ∠BOC =180°
∠AOC + 80° = 180°
∠AOC = 100°
Central Angle (at O) = Twice the Inscribed angle (at C)
100° = 2x
50° = x
5. In figure, AO = OB ( it is Radius)
So it is a Isosceles Trinangle
∠OAB = ∠OBA
∠OBA = 35°
Central Angle (at O) = Twice the Inscribed angle (at C)
∠AOB = 2x
Sum of Angles of Triangle = 180°
∠AOB +∠OBA+∠OAB = 180°
2x + 35° + 35° = 180°
2x = 180° - 70°
x = 110°/2
x = 55°
6. Extend the AO , perpendicular on BC ,say point E
In Triangle BEO
∠OBE + ∠OEB + ∠BOE = 180°
25° + 90° + ∠BOE = 180°
∠BOE = 180° - 115°
∠BOE = 65°
∠AOB+ ∠BOE = 180° (Sum of angle on straight line)
x + 65° = 180°
x = 115°