Plz tell the method to solve the following question in the attach ment
QUESTIONS 2,3,4
I don't need ans or solution I need the method to solve it QUE. 2,3,4
Plz help me....
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Okk
Thanks
Answers
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1) Let us assume : x= root(6+root(6 + root(6 + ………
So,
x= root(6+x)
x^2=6+x
x^2-x-6=0
(x-3)(x+2)=0
So, x=3 or -2.
But taking -2 as the answer would mean we are taking root of (-2) . Considering the fact that x belongs to the set of real numbers , we discard the solution x=-2.
So the answer is x =3.
2) X = √(3018+√{36+[√169]})
X = √[3018+√{36+13}]
X = √[3018+√(49)]
X = √[3018+7]
X = √3025
X = 55
3)Sorry ... I don't know 3rd ...
So,
x= root(6+x)
x^2=6+x
x^2-x-6=0
(x-3)(x+2)=0
So, x=3 or -2.
But taking -2 as the answer would mean we are taking root of (-2) . Considering the fact that x belongs to the set of real numbers , we discard the solution x=-2.
So the answer is x =3.
2) X = √(3018+√{36+[√169]})
X = √[3018+√{36+13}]
X = √[3018+√(49)]
X = √[3018+7]
X = √3025
X = 55
3)Sorry ... I don't know 3rd ...
Sis first is wrong aa given in hints and solutions
Pl.explain 2nd
Thanks
the formula for first i told u earlier uf applied when they are in multiplication not in addition ... for eg :- √6√6√6√6√6√6∞ = 6 ... i didnt saw adding sign first ...
Okk
U got the crown of brainiest
In 2nd...we took √169 =13 ....and then added it with 36 which gives us √49 which is equal to 7 ..and then added it to 3018 which gave √3025 = 55
ty
..
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rest i dont know