plz tell the procedure too. amd thx
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1/a +1/b +1/c = ab+bc+ca)/abc = 1
ab + bc +ca = 2
ab^2c^2 + a^2bc^2 +a^2b^2c
abc(ab+bc+ca) = 2×2 =4
ab + bc +ca = 2
ab^2c^2 + a^2bc^2 +a^2b^2c
abc(ab+bc+ca) = 2×2 =4
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It is solved in the picture
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