plz tell this 9th question plz
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it is given that the perimeter of the trapezium is 130m.
and BC=54m,CD=19m,AD=42m
so,AB+BC+CD+AD=130m
AB+54+19+42=130
AB=130-115
AB=15m
as we know that AB is perpendicular to BC
therefore it is height of the trapezium.
area of trapezium is 1/2×(sum of parallel sides)×height.
area=1/2×42+54×15
1/2×96×15
=720 square metres.
and BC=54m,CD=19m,AD=42m
so,AB+BC+CD+AD=130m
AB+54+19+42=130
AB=130-115
AB=15m
as we know that AB is perpendicular to BC
therefore it is height of the trapezium.
area of trapezium is 1/2×(sum of parallel sides)×height.
area=1/2×42+54×15
1/2×96×15
=720 square metres.
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