plz tell ..this question is from lines and angles
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x+3+x+20+x+7=180°
3x+30=180°
3x=180°-30°
3x=150
x=150÷3
x=50
3x+30=180°
3x=180°-30°
3x=150
x=150÷3
x=50
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Ans--- (x+20°)+(x+3)°+(x+7)°=180° [angle sum property)
3x+30°=180°
= 3x=180°-30°
3x=150°
Therefore, x=150/3
=50°
NOW, putting the value of x
Angle DBE=50°+3°=53°
AngleDBC=50°+20°=70°
AngleCBF=50°+7°=57° Ans........ Hope it help u......
3x+30°=180°
= 3x=180°-30°
3x=150°
Therefore, x=150/3
=50°
NOW, putting the value of x
Angle DBE=50°+3°=53°
AngleDBC=50°+20°=70°
AngleCBF=50°+7°=57° Ans........ Hope it help u......
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