Question

plz tell with format ​

Answer 1

Answer:

$2 { \cosec(30) }^{2} + x { \sin(60) }^{2} - \frac{3}{4} { \tan(30) }^{2} = 10 \\ 2 \times (2) {}^{2} + x \times (\frac{ \sqrt{3} }{2} ) {}^{2} - \frac{3}{4} \times ( \frac{1}{ \sqrt{3} } ) {}^{2} = 10 \\ 8 + \frac{3x}{4} - \frac{1}{4} = 10 \\ \frac{32 + 3x - 1}{4} = 10 \\ 31 + 3x = 40 \\ 3x = 9 \\ x = 3$

Answer 2

Answer:3

Hope it helps you.....