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Q.3
Let two numbers be A and B.
Then, A x B = LCM(A,B) x HCF(AB) ____i
A x B= 432(given)
And LCM(AB) =72(given)
To find HCF(AB),
From formula i, 432=72 x HCF(AB)
HCF(AB)=432/72
= 6
Q.4
The given numbers are 108,360 and 1296
Greatest number that divides
108,360 and 1296 should be less than 108 = its HCF
Now, HCF : (By prime factorisation method)
1296=2x2x2x2x3x3x3x3
360=2x2x2x3x3x5
108=2x2x3x3x3
Now, common from them:2x2x3x3=HCF=36
Hence,36 is the greatest number that divides
108,360 and 1296.
Q.5
I). - 9 +(-9)=-18
II). -84
Q.6
98+90-(-253)-43
=98+90+253-43______(- - = +)
=441-43
=398 Answer
Is it okay?
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