Question

plz this is urgent plz​

Answer 1

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$Given \: that \: 2x - 3y = 10 , xy = 16$

$\therefore(2x - 3y) {}^{3} = (10) {}^{3}$

$\longrightarrow \: 8 {x}^{3} - 27y {}^{3} - 3(2x)(3y)$

$(2x - 3y) = 1000$

$\longrightarrow8x {}^{3} - 27y {}^{3} - 18xy(2x - 3y) = 1000$

$\longrightarrow8x {}^{3} - 27y {}^{3} - 18(16)(10) = 1000$

$\longrightarrow8x {}^{3} - 27y {}^{3} - 2880 = 1000$

$\longrightarrow8x {}^{3} - 27y {}^{3} = 1000 + 2880$

$\longrightarrow8x {}^{3} - 27y {}^{3} = 3880$