Question

plz this two question ​

Answer 1

Step-by-step explanation:

(i) (3x2-4y2+5xy+20)-t = -x2-y2+6xy+20

3x2-4y2+5xy+20+x2+y2-6xy-20 = t

4x2-3y2-xy =t

(ii) (3x-y+11) + (-y-11)

3x -y+11 -y-11

3x-2y

(3x-2y)-(3x-y-11)

3x -2y-3x+y+11

-y +11

Answer 2

see above

answer with process given

hope it helps