plz....try to solve the que no.4
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Answered by
5
Think,
A={1,2,3,4,}
B={1,2 ,3,4,5,6}
A-B={1,2,3,4}-{1,2,3,4,5,6}=0
A union B={1,2,3,4} union {1,2,3,4,5,6}={1,2,3,4,5,6}=B
A intersection B={1,2,3,4} intersection {1,2,3,4,5,6}={1,2,3,4}=A
so this is the answer hope its help ☺
A={1,2,3,4,}
B={1,2 ,3,4,5,6}
A-B={1,2,3,4}-{1,2,3,4,5,6}=0
A union B={1,2,3,4} union {1,2,3,4,5,6}={1,2,3,4,5,6}=B
A intersection B={1,2,3,4} intersection {1,2,3,4,5,6}={1,2,3,4}=A
so this is the answer hope its help ☺
user32:
thank u so.....much........now i can go to give my test confidently....u r best!!!
Answered by
5
Heya !!
Here's your answer..⤵
_____________________
1) A ⊂ B
⊂ => subset
It means all element of set A are in set B.
2) A - B
It means those element of set A which do not belongs to set B.
from condition (1) and (2) ..,
we get A - B = ∅
∅ = empty set
3) A ∪ B = B
∪ => union
As we know all element of A are in B.
.... ( from (1) )
so we get A ∪ B = B
4) A ∩ B = A
∩ = intersection
as from (3) A ∪ B = B, so the common element of set A and set B is set A.
Hence, A intersection B we get A.
so, from (1) (2) (3) and (4) it's proved that all four condition were equivalent.
____________________________
Hope it helps
Thanks :)
Here's your answer..⤵
_____________________
1) A ⊂ B
⊂ => subset
It means all element of set A are in set B.
2) A - B
It means those element of set A which do not belongs to set B.
from condition (1) and (2) ..,
we get A - B = ∅
∅ = empty set
3) A ∪ B = B
∪ => union
As we know all element of A are in B.
.... ( from (1) )
so we get A ∪ B = B
4) A ∩ B = A
∩ = intersection
as from (3) A ∪ B = B, so the common element of set A and set B is set A.
Hence, A intersection B we get A.
so, from (1) (2) (3) and (4) it's proved that all four condition were equivalent.
____________________________
Hope it helps
Thanks :)
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