Question

plz try to solve this question if u r genius smart question 8​

Answer 1

Step-by-step explanation:

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Answer 2

$\: \: \longrightarrow{ \underline{{ \huge{ \tt{ A}}} \tt{NSWER :-}}}$

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${ \mathrm{ \longrightarrow {sin}^{2}30 \degree \: {cos}^{2}45\degree + 4 \: {tan}^{2}30 \degree + \dfrac{1}{2} {sin}^{2} 90\degree - 2 \: {cos}^{2} 90\degree + \dfrac{1}{24} {cos}^{2}0 \degree}}$

${ \mathrm{ : \longrightarrow{( { \dfrac{1}{2}) }^{2} }. \: ( { \dfrac{1}{ \sqrt{2} }) }^{2} + 4 \: ( { \dfrac{1}{ \sqrt{3} }) }^{2} + \dfrac{1}{2} \: ( {1)}^{2} - 2 \: ( {0)}^{2} + \dfrac{1}{24} \: ( {1)}^{2} }}$

We know that,

√a × √a = a

${ \mathrm{ : \longrightarrow{ \dfrac{1}{4} \times \dfrac{1}{2} + 4 \times \frac{1}{3} + \frac{1}{2} \times 1 - 2 \times 0 + \frac{1}{24} \times 1 }}}$

${ \mathrm{ : \longrightarrow{ \frac{1}{8} + \frac{4}{3} + \frac{1}{2} - 0 + \frac{1}{24} }}}$

${ \mathrm{ : \longrightarrow{ \frac{1}{8} + \frac{4}{3} + \frac{1}{2} + \frac{1}{24} }}}$

Now take the L.C.M,

=> 24

${ \mathrm{ : \longrightarrow{ \frac{3 +8 + 12 + 1}{24} }}}$

${ \mathrm{ : \longrightarrow{ \frac{ \cancel{24}}{ \cancel{24}} }}}$

${ \mathrm{ : \longrightarrow{ 1 \: \: \: ...(ans)}}}$

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Note :- For solving these types of sums, you just need to put the values of the given angles and simplify it further.

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