plz urgent give answer fast If p[x] = x square -x+1 then p[1]-p[-1] upon 2 is a) 0 b)2 c)-1 d)-2
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Answer:
d) -2
Step-by-step explanation:
p(x) = x²-x+1
p(1) = 1²-1+1
= 1
p(-1)=-1²-(-1)+1
=1+1+1
=3
p(1)-p(-1) = 1-3
= -2
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