Question

plz urgent h ....
$if \: a + b = 90 and \sec \: a \: = 2 \div 3 \: then \: find \: the \: value \: of \: \csc \: b.$
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Answer 1

heya!!!

secA=2÷3

also A+B=90

therefore

A=90-B

so secA = sec(90-B)

and sec(90-B)=cosB as sec(90-©)=cos©

so the answer of

cosB=sec(90-B)=2÷3

thanks!!!

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