Math, asked by ayushkumar6846, 1 year ago

plz very important ​

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Answered by Darsh05
1

Answer:

(i) (a²) × (2a²²) × 4a^{26}

=> (1 × 2 × 4) × (a² × a²² × a^{26})

=> 8 × a^{50}

=> 8a^{50}

(iii) (-\frac{10}{3} pq^{3}) *(\frac{6}{5} p^{3} q)\\\\=>(-\frac{10}{3} *\frac{6}{5}) *( pq^{3}* p^{3} q)\\\\=>(-2*2)*(p^{4} q^{4} )\\\\=>-4p^{4} q^{4}

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