Question

plz..
very urgent...
I need the correct answer.​

Answer 1

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Given :-

• CD = 1/3 BC

To Find :-

• Sin x/ Sin y x Cos x/ Cos y

Solution :-

TO KNOW :

$1. \: \boxed{ \sf {sin \: \theta = \frac{opp}{hyp} }} \\ 2. \: \boxed{ \sf {cos \: \theta = \frac{adj}{hyp} }}$

So, Sin x = AC/AD and Sin y = AC/AB

and Cos x = CD/AD and Cos y = CB/AB

$\sf{Hence \: \frac{sin \: x}{sin \: y} \times \frac{cos \: x}{cos \: y} } \\ \\ = \sf{ \frac{\frac{AC}{AD}}{ \frac{AC}{AB} } \times \frac{ \frac{CD}{AD} }{ \frac{CB}{AB} } } \\ \\ = \sf{ \frac{AB}{AD} \times \frac{AB}{AD} \times \frac{CD}{CB} } \\ \\ = \sf{ \frac{AB}{AD} \times \frac{AB}{AD} \times \frac{ \frac{1}{3} CB}{CB} } \\ \\ = \sf{ \frac{AB}{AD } \times \frac{AB}{AD} \times \frac{1}{3} } \\ \\ \star \: \underline{\boxed{ \sf{ = \frac{ {AB}^{2} }{3 {AD}^{2} } }}} \: \star$

@SweetestBitter

Answer 2

ʕ•ﻌ•ʔ$\huge\bold\pink{hello!!!}$ʕ•ﻌ•ʔ

HERE IS UR ANSWER

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refer attachment^^