Math, asked by siddhant9142, 9 months ago

plz want to no the ans

Attachments:

Answers

Answered by warrior24
1

volume of frustum of a cone = πh/3 [ R² + Rr + r² ]

on putting values

and solving v = 943.75 cm³ = 0.94375 litres

also TSA = πl ( R+r )

here l = √(R-r)² + h²

l = 41.23

on putting values

and solving TSA = 490.8738

Similar questions