Question

plz with full solutions plz jaldi
class9 ch Motion​

Answer 1

Explanation:

if train stop final velocity (v) =0

a=-5(retardation)

v=u+at

0=u+(-5)40

-u=-200

u=200m/s

s=ut+1/2at^2

s=200×40+1/2×-5×(40)^2

s=8000+1/2×-5×1600

s=8000+(-4000)

s=8000-4000

s=4000m

Answer 2

To find:-

Initial Velocity (u) = ?

Distance (s) = ?

Given,

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s

time taken (t) = 40 second .

Solution:-

$v = u + at \\ = > 0 = u + ( - 5 \times 200) \\ = > 0 = u - 200 \\ = > u = 200 \frac{m}{s}$

And

$s = ut + \frac{1}{2} \times a {t}^{2} \\ = > s = 200 \times 40 + \frac{1}{2} \times - 5 \times {40}^{2} \\ = > s = 8000 - 4000 \\ = > s = 4000meter$

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