Plz zzz ans this question.. How to solve step by step
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Answer:
the change in enthalpy is +492kJ
Explanation:
the final equation is the sum of reverse of first and second
so the enthalpy of first equation will change its sign so it I'll be +822 KJ
now
as we know that change in enthalpy is
∆H = H2 - H1
so
∆H = 3 * (-110) + 822
∆H = -330 + 822
∆H = +492kJ/mol
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