Question

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Answer 1

Question :-

If $\rm \sqrt[3]{2x - 3} - 4 = 0$ ,then x =

Concept :- By transposing 4 on right side and then cubing on both side, we can get a simple linear equation, and by solving the linear equation, we can get the value of x

Solution :-

➱ $\rm \sqrt[3]{2x - 3} - 4 = 0$

➱ $\rm \sqrt[3]{2x - 3} = 4$

On cubing both sides and solving :-

➱ $\rm (\sqrt[3]{2x - 3})^3 = 4^3$

➱ $\rm 2x - 3 = 64$

➱ $\rm 2x = 64 + 3$

➱ $\rm 2x = 67$

➱ $\rm x = \frac{67}{2}$

➱ $\boxed{\rm x = 33.5 }$