Question

Plzs answer q no 3 and 4

Answer 1

Explanation:

Q.3) initial velocity,u=0m/s,

acceleration, a=0.2m/s2

time=5min=60s

final velocity, v=?

distance, s=?

since, acceleration = (v - u)/t

=>0.2=(v -0)/60

=>v =0.2 × 60

=>v =12m/s

now,

distance, s = ut + 1/2at2

s = 0 ×60 + 1/2×0.2×(60)2

s = 360m

Q.4) (a) u =0m/s, a= 4m/s2, t =10s

since, a= (v - u)/t

4 = (v - 0)/10

4 = v/10

v = 40m/s

(b) distance = ut + 1/2at2

= 0 ×10 + 1/2 ×4 ×(10)2

= 200m

Hope it helps u