Question

Plzz ans 2,3and 4 ques

Answer 1

3)KE=1/2×m×v^2
KE1=1/2×m1×(1/2v)^2
KE1 =1/2×m× 1/4v^2
KE1 =1/4 [1/2× m× v^2)
KE1 = 1/4KE
1/4=KE1/KE
1/4=1/2m1×1/4 v^2/1/2m v^2
1/4=m1×1/4/m
m=m1
therefore mass remains same
4) M=2kg
u=0
v?
5)KE =KE1
1/2×m×v^2= 1/2×1/4m×v1^2
V^2=1/4×v1^2
v=1/2v1
therefore the actual velocity is half the new velocity