Question

plzz ans all the parts

Answer 1

HEY MATE HERE IS YOUR ANSWER

As the three angles are in AP the three angles are 30 60 90

But WKT
C = 90
A=60
B=30

Then here is your answers

$\sin(a) + \sin(b) + \sin(c) \\ \sin(60) \sin(30 ) \sin(90) \\ \frac{ \sqrt{3} }{2} + \frac{1}{2} + 1 \\ \frac{ \sqrt{3} + 1 + 2}{2} \\ \frac{ \sqrt{3} + 3}{2}$
cosA +cosB + cosC
cos60+cos30+cos90
$= \frac{1}{2} + \frac{ \sqrt{3} }{2} + 0 \\ \frac{ \sqrt{3} + 1}{2}$

sin2A+sin2B+sin2C
sin2 (60)+sin2 (30)+sin2 (90)
sin(90+30)+sin60+sin(90+90)
cos30+sin60+cos90
[tex]\frac {\sqrt {3}+\sqrt{3}}{2}
\frac {\sqrt {3}}
Hence from this we can say that
1 (R)
2 (S)
3 (Q)
4 (P)

HOPE IT HELPS YOU

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