Question

Plzz ans fast my exam r nearear ans question 6th only.Plz fast

Answer 1

Let smallest angle be x
Therefore the angles are x:2x:2x:5x
Sum of angles in quadrilateral is 360
Therefore x+2x+2x+5x=360
10x=360
x=360/10
x=36
Smallest angle is 36
Largest angle is 5x=5×36=180
Difference between largest and smallest angle is
180-36=144
Hope this helps!! Please mark me brainliest

Answer 2

Let the angle be X
1 = X
2 = 2X
2 = 2X
5 = 5X

We know that sum of all angles of a quadrilateral = 360°

A/q

X + 2X + 2X + 5X = 360°
=> 10X = 360°
=> X = 360°/10 = 36°

Hence,
X = 36°
2X = 2×36° = 72°
2X = 2×36° = 72°
5X = 5×36° = 180°

Largest angle = 180°
Smallest angle = 36°

Difference between largest angle and smallest angle = 180°-36°
= 144°


So,
144° ans.