Question

plzz ans h2 nd h3 ..its urgent

Answer 1

H-2 ❤️❤️




Let, we are sitting inside the trolley,
Let the acceleration of block be a.
mass of trolley M = 8Kg
mass of block m = 2Kg
theta = 37'
A pseudo force  will act in the opposite direction to the acceleration of the trolley and it will be equal to 
Fp = m x a
By drawing FBD, you will get that
T Sin Theta = Fp ------1
T Cos Theta = mg ----- 2
eq 1 / eq 2
we get
tan theta = a/g
(3g)/4 = a
So option 1 is wrong.
Now
Force applied = (m + M) x a
F = 10 x 3g /4
F = 75N
So option 2 is wrong and option 3 is correct.
now Tension
using eq1
T x 3/5 = 8 x 3g/4
T = 10g
T = 100N



So correct choice is : option 3 ✌️✌️✌️




H-3 ❤️❤️


In this case M and m are moving with the same acceleration a. Note that a is along x-direction only

For M and m :

F−N2sinθ=Ma--------(1)

mg−N2cosθ=0

⇒N2=mg/cosθ ----(2)

N2sinθ=ma------(3)

From (2) and (3),

a=gtanθ

Substitute (3) into (1) obtains

F=(M+m)a

=(M+m)gtanθ