plzz ans it.........
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x=5 or x=1
Step-by-step explanation:
In triangle PQT
PQ || RS and PT is their transversal
<TRQ = <TRS .....,.......(1)
PQ || RS and QT is their transversal
<TQP = <TSR ...............(2)
In triangle TPQ and triangle TRS
<TRQ = <TRS .........from (1)
<TQP =<TSR ...........from(2)
triangle TPQ ~ triangle TRS
TP/TR = PQ/RS
x+3+x-1/x-1 =x+1/x-3
2x+2/x-1=x+1/x-3
(2x+2)(x-3)=(x+1)(x-1)
2xsquare -6x +2x -6 =x square -1
2xsquare -4x -6 = xsquare -1
2xsquare - xsquare -4x -6 +1=0
xsquare -4x -5=0
xsquare -5x +1x -5 =0
x(x-5) -1(x-5)=0
(x-5)(x-1)=0
x-5 =0 or x-1=0
x=5 or x=1
this will helps you
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