Math, asked by class102, 1 year ago

plzz ans..:-)little fast with steps

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Answered by InvincibleBoy
1
Heya!!!!

◆Answer:-

4x^2-2(a^2+b^2)x+a^2b^2=0

→4x^2-2a^2.x-2b^2.x+a^2b^2=0

→2x(2x-a^2)-b^2(2x-a^2)=0

→2x-a^2=0 <---> 2x-b^2=0

→2x=a^2 <-------->2x=b^2

→x=a^2/2 <------->x=b^2/2

Hope My Answer Helped

class102: oh kk tq
hdewangan: I tried but my I can't find the answer
hdewangan: m so sorry
class102: oh kk tq no problem bro
hdewangan: thnx
class102: dont be sry
hdewangan: thnx sis
class102: can u just try my new one if u r free only
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