plzz ans......Logarithms.......Thnk you
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log2 (x + y) = log3 (x - y) = log25/log0.2
log2 (x + y) = log5²/log1/5 = 2log5/-log5
log2 (x + y) = -2
(x + y) = 2^-2 = 1/4 -----(1)
again,
log3 (x - y) = 2log5/-log5 = -2
(x - y) = 3^-2 = 1/8 ------(2)
solve eqn (1) and (2)
2x = 1/4 +1/9 = 13/36
x = 13/72 and y = 1/4 - 13/72 = 5/72
hence, x = 13/72 and y = 5/72
log2 (x + y) = log5²/log1/5 = 2log5/-log5
log2 (x + y) = -2
(x + y) = 2^-2 = 1/4 -----(1)
again,
log3 (x - y) = 2log5/-log5 = -2
(x - y) = 3^-2 = 1/8 ------(2)
solve eqn (1) and (2)
2x = 1/4 +1/9 = 13/36
x = 13/72 and y = 1/4 - 13/72 = 5/72
hence, x = 13/72 and y = 5/72
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