plzz ans my question
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Given that
pressure due to atmosphere = 1.013 × 10^5 Pascal
Length of table surface = 2m
width of table surface = 1m
then area = 2m^2
now as pressure = force/area
area = 1m^2
then force = 1.013 × 10^5 N
then pressure = (1.013 × 10^5)/2
= 0.5065 × 10^5 Pascal
or = 5.065 × 10^4 Pascal
pressure due to atmosphere = 1.013 × 10^5 Pascal
Length of table surface = 2m
width of table surface = 1m
then area = 2m^2
now as pressure = force/area
area = 1m^2
then force = 1.013 × 10^5 N
then pressure = (1.013 × 10^5)/2
= 0.5065 × 10^5 Pascal
or = 5.065 × 10^4 Pascal
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