Question

plzz ans my question

Answer 1

electronic configuration of beryllium is =2,2
while that of oxygen is 2,6
so their valency is +2 and -2

Answer 2

$\huge \bold {HEYA!!}$

$\huge \mathfrak {ANSWER:}$

☆ ELECTRONIC CONFIGURATION:

■ OF Be :

Since it is 4 ,

it is $\boxed {2,2}$

■ REASON:
________

As u know the way of filling electrons in the shell...

the rule is 2, 8 , 16 , 32, ........

●it means that in first shell, only two electrons can be filled, in second shell 8 electrons can be filled and so on....

●so for beryllium since it has total four electrons .
in first shell we can fill two electrons na, and the remaining two electrons will be filled in next shell..
so it 2,2

■ OF O :

•Since it is 8,

it is $\boxed {2,6}$

REASON:
________

●same as in beryllium. since oxygen has eight electrons, according to that rule, first two electrons are filled in first shell , and remaining electrons, 6 electrons are filled in next shell.. so it is 2,6

☆ VALENCY:

● Valency of Be = 2

•because valency is always equal to number of valence electrons . so valence electrons in Be is 2 .that's why valency is 2

or u can say ... that....if it loses two electrons it becomes stable na....so it is 2 ...

● valency of O = 2

•here oxygen needs two more electrons to complete its octet . so its valency is 2.


$\huge \red {♡BE \: BRAINLY♡}$