Plzz ans need fast..solve it from cicle
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join AB.
In ABC, AB = BC
So, <A = <C
<B = 180° - (<A + <B)
= 180° -(25° + 25°)
= 180° - 50°
= 130°
Since the angle in circumference is twice the angle in centre, so
<B = 2<AOC
130° = 2 × x
x= 130/2
x = 65°
In ABC, AB = BC
So, <A = <C
<B = 180° - (<A + <B)
= 180° -(25° + 25°)
= 180° - 50°
= 130°
Since the angle in circumference is twice the angle in centre, so
<B = 2<AOC
130° = 2 × x
x= 130/2
x = 65°
sudhu58:
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