plzz ans....Quadratic equation...Thnk u
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Hey there!!
Down here ⏬
☆ Given :
CP = ₹60 x
SP = ₹ (500+4x)
Loss % = x%
CP = ?
☆ CP = 100×SP/(100-Loss%)
CP = 100×(500+4x) / (100-x)
= 50000+400x/(100-x)
= 500+400x / -x
= 500-400 = ₹100
☆ Therefore, CP = ₹100
Hope it helps.
<3
Down here ⏬
☆ Given :
CP = ₹60 x
SP = ₹ (500+4x)
Loss % = x%
CP = ?
☆ CP = 100×SP/(100-Loss%)
CP = 100×(500+4x) / (100-x)
= 50000+400x/(100-x)
= 500+400x / -x
= 500-400 = ₹100
☆ Therefore, CP = ₹100
Hope it helps.
<3
AkshithaZayn:
tq
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