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given:(a+b)=10, a²+b²=58
then a³+b³=?
sol:- (a³+b³)=(a+b)(a²-ab+b²)
(a³+b³)=10(58-ab).......(i)
(a+b)²=a²+2ab+b²
(a+b)²=58+2ab
(10)²=58+2ab
-2ab=100-58
-ab=42÷2
-ab=21
now putting the value of '-an ' in equation 1st
(a³+b³)=10(58-21)
(a³+b³)=10(37)
a³+b³=370 ans.
then a³+b³=?
sol:- (a³+b³)=(a+b)(a²-ab+b²)
(a³+b³)=10(58-ab).......(i)
(a+b)²=a²+2ab+b²
(a+b)²=58+2ab
(10)²=58+2ab
-2ab=100-58
-ab=42÷2
-ab=21
now putting the value of '-an ' in equation 1st
(a³+b³)=10(58-21)
(a³+b³)=10(37)
a³+b³=370 ans.
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