Question

plzz ans this now plzz​

Answer 1

Given:

CSA of cylinder = 4400$\sf{cm^2}$

Circumference of base = 110$\sf{cm}$

To find:

Height of the cylinder(h)

Solution:

Let the radius of thr cylinder be h.

Circumference = $\sf{2\pi r}$

$\sf{\implies 110=2 \times \frac{22}{7} \times r}$

$\sf{\implies r=\frac{110 \times 7}{22 \times 2} }$

$\bf{\therefore r=17.5cm}$

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$\sf{CSA =2 \pi r h}$

$\sf{\implies 4400= 2 \times \frac{22}{7} \times 17.5 \times h}$

$\sf{\implies h= \frac{4400 \times 7}{2 \times 22 \times 17.5}}$

$\sf{\implies 110 \times h = 4400}$

$\boxed{\bf{\therefore h=40}}$

Therefore, height of the cylinder is 40cms.

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@zaqwertyuioplm :)