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trishagupta:
a tough question nd so less points.
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Area of semi-circle PQR = ½π(9/2)2
= 81π/8 cm2
Area of region circle, A = π(9/4)2
= 81π/16 cm2
Area of region (B + C) = π(3/2)2
= 9π/4 cm2
Area of region D = ½π(3/2)2
= 9π/8 cm2
Area of shaded region = Area of semicircle - Area of circle - Area of region (B + C) + Area of region D
= 81π/8 - 81π/16 - 9π/4 + 9π/8
= 63π/16 cm2
= 99/8 cm2
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= 81π/8 cm2
Area of region circle, A = π(9/4)2
= 81π/16 cm2
Area of region (B + C) = π(3/2)2
= 9π/4 cm2
Area of region D = ½π(3/2)2
= 9π/8 cm2
Area of shaded region = Area of semicircle - Area of circle - Area of region (B + C) + Area of region D
= 81π/8 - 81π/16 - 9π/4 + 9π/8
= 63π/16 cm2
= 99/8 cm2
hope it helps
please mark it as brainliest
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