Question

plzz ans.....Thnk u.....PROVE THE FOLLOWING

Answer 1

HEYA!!

YOUR SOLUTION IS IN THE ATTACHMENT.

#KEVIN

HOPE IT HELPS YOU ☺

Answer 2

HELLO DEAR,

we know that:-

a²-b² =(a-b)(a+b)----------(1)
$\frac{ \cos\alpha }{1 - \tan \alpha } - \frac{ {sin}^{2} \alpha }{ \cos \alpha - \sin \alpha } \\ \\ = \frac{ \cos \alpha }{1 - \frac{ \sin \alpha }{ \cos \alpha } } - \frac{ {sin}^{2} \alpha }{ \cos \alpha - \sin \alpha } \\ \\ = \frac{cos \alpha }{ \frac{cos \alpha - sin \alpha }{cos \alpha } } - \frac{ {sin}^{2} \alpha }{cos \alpha - sin \alpha } \\ \\ = \frac{ {cos}^{2} \alpha }{cos \alpha - sin \alpha } - \frac{ {sin}^{2} \alpha }{cos \alpha - sin \alpha } \\ \\ = \frac{( {cos}^{2} \alpha - {sin}^{2} \alpha) }{cos \alpha - sin \alpha } \\ \\ = \frac{(cos \alpha - sin \alpha )(cos \alpha + sin \alpha )}{(cos \alpha - sin \alpha )} from \: .(1)\\ \\ = (cos \alpha + sin \alpha )$
I HOPE ITS HELP YOU DEAR,
THANKS