Question

plzz ans....Thnk you....Logarithms

Answer 1

Hey there !!!!!

Taking LHS

logx/y*logxy- -- -- - - Equation 1

We can write logx/y as logx - logy and logxy as logx+logy

So equation 1 changes to 

=(logx-logy)(logx+logy)----------Equation 2

Now equation 2 is of the form  (a+b)(a-b)=a²-b²

Here a=logx  b=logy

So,

(logx+logy)(logx-logy)=(logx)²-(logy)²

  LHS=RHS

Hope this helped you...........