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♦Given that ..
tan = 1/√3
tan theta = tan 30
theta =30
now , cosec^2 30 - sec^2 30/ cosec ^2 30+ sec^2 30..
2^2-2√3^2 / 2^2+2√3
4-4/3/4+4/3
12-4/12+4
8/16
1/2 ...
I hope it help's u...✌✌✌
♦Given that ..
tan = 1/√3
tan theta = tan 30
theta =30
now , cosec^2 30 - sec^2 30/ cosec ^2 30+ sec^2 30..
2^2-2√3^2 / 2^2+2√3
4-4/3/4+4/3
12-4/12+4
8/16
1/2 ...
I hope it help's u...✌✌✌
singarapusreehanth6:
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