plzz answer 25th and 26th
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25) In ΔAOD,by angle sum property,
x+x-6+90=180
⇒2x=180-84
x=96/2=48°
similarly, in ΔBOC,
4y+3y+6+90=180
⇒7y=180-96
⇒y=84/7= 12°
26) ∵∠x=∠y
⇒180-x=180-y
i.e. ∠QSR=∠PEQ
in ΔPEQ & ΔRSQ,
PQ=QR
∠QSR=∠PEQ
∠Q=∠Q
∴by AAS congruence rule,
ΔPEQ ≡ ΔRSQ
by CPCT,
PE=RS
x+x-6+90=180
⇒2x=180-84
x=96/2=48°
similarly, in ΔBOC,
4y+3y+6+90=180
⇒7y=180-96
⇒y=84/7= 12°
26) ∵∠x=∠y
⇒180-x=180-y
i.e. ∠QSR=∠PEQ
in ΔPEQ & ΔRSQ,
PQ=QR
∠QSR=∠PEQ
∠Q=∠Q
∴by AAS congruence rule,
ΔPEQ ≡ ΔRSQ
by CPCT,
PE=RS
Manjaree2003:
Hope it helps!!!!
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hope it helps ......
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