plzz answer all of these
Answers
Answer:
1. 44cm
2. 9/25
3.11.8cm
4. 31.4m²
5.29.9cm
Step-by-step explanation:
Area of square= 121cm²
121=a²
or a=11cm
now perimeter= 4*a
=4*11=44cm
2.ratio=3r:5r
π3r*3r/π5r*5r
3r*3r/5r*5r=9/25
3.Area of parallelogram=b*h
95=8*h
h=95/8=11.8cm
4.area of quadrant=1/4*π*r*r
1/4*22/7*10*10=31.4m²
5.perimeter of triangle=circumference of circle
31.4*3=22/7*d
d=29.9cm
Answer:
Step-by-step explanation:
1). Area of square = side*side
121 = side²
(11)² = side²
11cm = side
Perimeter = 4*side
= 4*11 = 44cm
2). Let the radius of those circles be 3x and 5x respectively.
Area of circle = πr2
Now area of 1st cirlce = π(3x)² = 9πx²
area of 2nd circle = π(5x)²= 25πx²
Now their ratio becomes :
area of 1st cirlce: area of 2nd circle
9πx² : 25πx²
= 9:25
3). Area of parallelogram =
base*height
= 96 = 800*h
= 96/800 = h
= 12/100 = h
= 0.12 = h
4). Radius =10m and centre at pole.
Area swept by the rope in 1 complete rotation = Area of the circle
=πr²
=3.14×10²
=3.14×100
=314m²
5). Side of equilateral triangle = 31.4
cm
Perimeter = 3*side
Perimeter = 3 ( 31.4) = 94.2 cm
Given, Perimeter of triangle = Peri meter of Ring.
πd = 94.2
(3.14)d = 94.2
d = 94.2/3.14
d = 30 cm.