Question

Plzz answer all the question given below

Answer 1

Answer:  Explanation:     1. the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.    2.Total initial momentum = Total final momentum Since, Initially both gun and bullet is at rest, their initial momentum is zero.  Let the recoil velocity be V.  0 = 5V - (10/1000)×500 > 5V = 5 > V = 1 m/s   3.M= mass of the boy = 50 kg  V = initial velocity of the boy before jumping into cart =  6m/s  m = mass of stationary cart = 10kg  v = velocity of stationary cart = 0 m/s  V' = velocity of boy and cart combination after collision  Using conservation of momentum  M V + m v = (M + m) V'  (50) (6) + (10) (0) = (50 + 6) V'  V' = 310/56  V' =  5.535m/s     4  initial momentum= final momentum.. common velocity means both trolley and boy moves with same velocity.. now.. initial momentum=60×8+10×1 =480+10 =490 kgm/s final momentum=(60+10)V 70V so on equating.. 70V=490 V=490/70=7m/s    5.Given :-  Mass of the bullet = 0.01 kg  Mass of the target = 400 g  = 400 × 10⁻³ kg  Initial speed of the target = 10 m/s  Final speed of the bullet = 0 m/s  Final speed of the target = 0 m/s  To Calculate :-  Initial speed of the bullet = ??  Formula to be used :-  m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂  = (0.01 × 0) + (400 × 10⁻³ × 0)  or (0.01 u₁) + 4 = 0  or 0.01 u₁ = - 4  or u₁ = - 4/0.01  u₁ = - 400 m/s.  Hence, the velocity of the bullet at the time of striking the target is  - 400 m/s.    MARK AS BRAINLIEST PLZ...................