Question

Plzz answer as possible

Answer 1

heya.....



By Euclid's Division Algorithm,


237=81(2)+(75)


81=75(1) + (6)


75=6(12)+(3)


6=3(2)+(0)


Hcf =3


Expressing it in the form of 237x+81y=HCF


3=75-6(12) { From 2nd last step}


3=75-(81-75)(12) {Substituting}


3=75-(81*12-75*12)


3=75-81*12+75*12


3=75(13)-81(12)


3=(237-81*2)(13)-81(12)


3=237(13)-81(38)


3=237(13)+81(-38) {we need an expression in the form 237x + 81y }


Therefore, x =13 , y =- 38


tysm.#gozmit

Answer 2

Hey mate!

Here's your answer!!

237=81*2+75..........(1)
81=75*1+6.........(2)
75=6*12+3..........(3)
6=3*2+0.........(4)

So the HCF of 81 and 237 will be 3.

Now to expresss it as a linear combination of 81 and 237 .

From (3) we have ,

•3=75-6×12

=>3=75-(81-75×1)×12

=>3=13×75-12×81

=>3=13×(237-81×2)-12×81

=>3=13×237-26×81-12×81

=>3=13×237-38×81

=>3=237x+81y,

where x=13 and yb= -38.

$hope \: it \: helps \: you.$
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