plzz answer fast............
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Hey !!
Check the attachment.
Hope it helps :)
Check the attachment.
Hope it helps :)
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Heya User,
--> Say, base radius = 'r' || height = 'h'
--> Then, C.S.A. = 2πrh || T.S.A = 2πr² + 2πrh
ATQ -->
---> T.S.A. = 3 C.S.A.
=> 2πr² + 2πrh = 3 [ 2πrh ]
=> 2πr² + 2πrh = 6πrh
=> 2πr² = 4πrh
=> r ( r - 2h ) = 0
However, if r = 0, the question has a dead end =_=
So, I'll take r ≠ 0 ;
=> r = 2h
Now, CSA = 154 cm²
=> 2πrh = 154 cm²
=> πr² = 154cm²
=> r² = 49 cm²
=> r = 7 cm ---> h = 7/2 cm
Now, Volume = ( πr² ) h = 154 * 7/2 = 539 cm³
There we go +_+ ... Volume of Cylinder = 539 cm³
--> Say, base radius = 'r' || height = 'h'
--> Then, C.S.A. = 2πrh || T.S.A = 2πr² + 2πrh
ATQ -->
---> T.S.A. = 3 C.S.A.
=> 2πr² + 2πrh = 3 [ 2πrh ]
=> 2πr² + 2πrh = 6πrh
=> 2πr² = 4πrh
=> r ( r - 2h ) = 0
However, if r = 0, the question has a dead end =_=
So, I'll take r ≠ 0 ;
=> r = 2h
Now, CSA = 154 cm²
=> 2πrh = 154 cm²
=> πr² = 154cm²
=> r² = 49 cm²
=> r = 7 cm ---> h = 7/2 cm
Now, Volume = ( πr² ) h = 154 * 7/2 = 539 cm³
There we go +_+ ... Volume of Cylinder = 539 cm³
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