Math, asked by navneet1284, 4 months ago

plzz answer fast..................​

Attachments:

Answers

Answered by Anonymous
5

hope it helps you plz mark as brainliest

Step-by-step explanation:

c is the correct answer

Answered by JashanR
5

Answer:

Given- O is the centre of a circle to which a pair of tangents PQ&PR from a point P touch the circle at Q&R respectively. ∠RPQ=60

o

.

To find out- ∠ROQ=?

Solution- ∠OQP=90

o

=∠ORP since the angle, between a tangent to a circle and the radius of the same circle passing through the point of contact, is 90

o

. ∴ By angle sum property of quadrilaterals, we get ∠OQP+∠RPQ+∠ORP+∠ROQ=360

o

⟹90

o

+60

o

+90

o

+∠ROQ=360

o

⟹∠ROQ=120

o

.

Attachments:
Similar questions