Plzz answer fast
How many atoms and molecules are present in 64.0gm of sulphur.
Answers
Answered by
26
64g of S
Molecular Mass of Sulphur = 32g/mol
64g of S/ 32 g/mol = 2 mol
1 mol = 6.022 x 1023 atoms
2 mol * 6.022 x 1023
=1.2044 x 1024 atoms of S
1 molecule of S = 8 atoms
1.2044 x 1024 /8 = 1.5055 x 1023 molecules of S
Molecular Mass of Sulphur = 32g/mol
64g of S/ 32 g/mol = 2 mol
1 mol = 6.022 x 1023 atoms
2 mol * 6.022 x 1023
=1.2044 x 1024 atoms of S
1 molecule of S = 8 atoms
1.2044 x 1024 /8 = 1.5055 x 1023 molecules of S
SHIVAANSHSINGH:
1023=10^23
Answered by
10
Number of atomsof sulphur (S8) = 8 x 1.50 × 1023 molecules = 1.20× 1023 atoms.
Similar questions